Question

What is the angle of elevation of the sun when the length of the shadow of the pole is $1/\sqrt{3}$ times the height of the pole?

• A. ${30}^o$
• B. ${45}^o$
• C. ${60}^o$
• D. ${75}^o$

Answer 1

Answer: (C)

${60}^o$

Shadow of pole = $\frac{1}{\sqrt{3}}$ Height of Pole
$S=\frac{H}{\sqrt{3}}$
Let angle of elevation be $\theta$
Now, $\tan \theta =\frac{H}{S}$
$\tan \theta =\sqrt{3}$
$\tan \theta =\tan 60$
$\theta ={60}^{\circ }$