What is the angle of incidence of a ray if the reflected ray if the reflected ray is at an angle of 90 degree to the incident ray- Answer is 45 degree- But my physics teacher tells that answer in 90 degree - Please explain-

You are correct... Understanding the below solution please ask again to your teacher. We know that the angle of incidence is equal to the angle of reflection. ...

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Byju's Answer

Standard VIII

Physics

Laws of Reflection

What is the a...

Question

What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

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Solution

We know that the angle of incidence is equal to the angle of reflection.
∠i = angle of incident.
∠r = angle of reflection.

Given: ∠i + ∠r = 90°
Since ∠i = ∠r hence;
∠i + ∠i = 90°
Or, 2∠i = 90°
Or, ∠ i= 45°.

Thus, the angle of incidence is 45°.

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Q. A ray of light from a denser medium strikes a rare medium at angle of incidence i as shown in the figure. The reflected and refracted rays make an angle of 90°with each other. The angles of reflection and refraction are r and r'. The critical angle between them is

(a) sin^-1(tanr)
(b) sin^-1(tani)
(c) sin^-1(tanr')
(d) tan^-1(tani)

(The figure has an incident ray , a reflected ray , a normal and a refracted ray all lying at the point of incidence and an angle of 90 degree btw reflected and refracted ray)

*(Sir/madam please send a detailed answer along with the explanation of the QUESTION)

What is the angle of incidence of a ray of light if the reflected ray is at an angle of $90^{\circ}$ to the incidence ray?

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What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

We know that the angle of incidence is equal to the angle of reflection.∠i = angle of incident.∠r = angle of reflection. Given: ∠i + ∠r = 90° Since ∠i = ∠r hence; ∠i + ∠i = 90° Or, 2∠i = 90° Or, ∠ i= 45°.Thus, the angle of incidence is 45°.

We know that the angle of incidence is equal to the angle of reflection.
∠i = angle of incident.
∠r = angle of reflection.

Given: ∠i + ∠r = 90°
Since ∠i = ∠r hence;
∠i + ∠i = 90°
Or, 2∠i = 90°
Or, ∠ i= 45°.

Thus, the angle of incidence is 45°.