Question

what is the angular momentum of an electron of de$-$broglie wavelength $\lambda ?$ given $r$ is the radius of orbit$.$

• A. $\frac{rh}{\lambda }$
• B. $\frac{2rh}{\lambda }$
• C. $\frac{3rh}{\lambda }$
• D. $\frac{4rh}{\lambda }$

Answer 1

The correct option is A $\frac{rh}{\lambda }$

$mvr=\frac{h}{\lambda }$

$r=\frac{rh}{\lambda }$

Hence,

option $\left(A\right)$ is correct answer.