What is the angular velocity of earth?

\frac{2 π}{86400} r a d / s e c

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\frac{2 π}{3600} r a d / s e c

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\frac{2 π}{24} r a d / s e c

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\frac{2 π}{6400} r a d / s e c

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Solution

The correct option is A $\frac{2 π}{86400} r a d / s e c$
Time taken by earth to complete 1 revolutions = t = $24 hours = 24 \times 60 \times 60 = 86400$ secs
Frequency of the revo;utions of the earth = $f = \frac{1}{t} = \frac{1}{86400} s e c^{- 1}$
Angular velocity of the earth = $ω = 2 π f = \frac{2 π}{86400} r a d / s e c$

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What is the angular velocity of earth?

The correct option is A 2π86400rad/secTime taken by earth to complete 1 revolutions = t = 24hours=24×60×60=86400 secsFrequency of the revo;utions of the earth = f=1t=186400sec−1Angular velocity of the earth =ω=2πf=2π86400rad/sec