Question

What is the answer of :
$\frac{sec17}{cosec73}+\frac{tan68}{cot22}+co{s}^{2}44+co{s}^{2}46$

Answer 1

$\frac{sec{17}^o}{sec({90}^o-{73}^o)}+\frac{tan{68}^o}{tan({90}^o-{22}^o)}+co{s}^2{44}^o+si{n}^2({90}^o-{46}^o)$

$=\frac{sec{17}^o}{sec{17}^o}+\frac{tan{68}^o}{tan{68}^o}+co{s}^2{44}^o+si{n}^2{44}^o$

$=1+1+1$

$=3$