Question

What is the approximate energy equivalent (in MeV) to mass of a proton?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{E}={\mathrm{m}}_{\mathrm{p}}{\mathrm{c}}^2 \\ \mathrm{mass}\mathrm{of}\mathrm{proton},{\mathrm{m}}_{\mathrm{p}}=1.67\times {10}^{-27}\mathrm{kg} \\ \mathrm{velocity}\mathrm{of}\mathrm{light},\mathrm{c}=3\times {10}^8\mathrm{m}/{\mathrm{s}}^2 \\ \mathrm{E}=1.67\times {10}^{-27}\times {\left(3\times {10}^8\right)}^2 \\ \mathrm{E}=1.503\times {10}^{-10}\mathrm{J} \\ 1\mathrm{Joule}=6.24\times {10}^{12}\mathrm{MeV} \\ 1.503\times {10}^{-10}\mathrm{J}=6.24\times {10}^{12}\times 1.503\times {10}^{-10} \\ \mathrm{E}=937.87\mathrm{MeV} \end{gathered}$$