What is the approximate length of the longer leg of triangle $E F G$ ?

4.23

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4.66

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9.06

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11.03

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Solution

The correct option is A $4.23$

$\Rightarrow sin 25 ° = \frac{F G}{E G} = \frac{F G}{10}$
$\Rightarrow F G = 10 sin 25 °$
$= 10 \times 0.423$
$= 4.23 m .$
Hence, the answer is $4.23$

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What is the approximate length of the longer leg of triangle EFG?

The correct option is A 4.23⇒sin25°=FGEG=FG10⇒FG=10sin25° =10×0.423 =4.23m.Hence, the answer is 4.23

What is the approximate length of the longer leg of triangle $E F G$ ?

The correct option is A $4.23$

$\Rightarrow sin 25 ° = \frac{F G}{E G} = \frac{F G}{10}$
$\Rightarrow F G = 10 sin 25 °$
$= 10 \times 0.423$
$= 4.23 m .$
Hence, the answer is $4.23$