What is the approximate molecular mass of dry air containing 78% $N_{2}$ and 22% $O_{2}$ ?

28.88

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Solution

The correct option is A 28.88
The molecular mass of dry air is given by-

$= \frac{[Molecular mass of N_{2} \times Percentage of N_{2}] + [Molecular mass of O_{2} \times Percentage of O_{2}]}{Percentage of N_{2} + Percentage of O_{2}}$

$= \frac{[28 \times 78] + [32 \times 22]}{78 + 22}$

$= 28.88 g/mol$

Hence, option $A$ is correct.

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