Question

What is the approximate peak value of an alternating current producing four times the heat produced per second by a steady current of $2A$ in a resistor?

• A. $2.8A$
• B. $4.0A$
• C. $5.6A$
• D. $8.0A$

Answer 1

The correct option is C $5.6A$

$I_{rms}=2\times i_{steady}...............\left(i\right)$

Also,

$I_{rms}=\frac{I_{max}}{\sqrt{2}}...................\left(ii\right)$

From (i) and (ii)

$\frac{I_{max}}{\sqrt{2}}=2\times i_{steady}$

Here $i_{steady}=2A$

So,

$I_{max}=\sqrt{2}\times 2\times 2$

$I_{max}=5.6A$