What is the approximate peak value of an alternating current producing four times the heat product per second by a steady current $2$ A in a resistor ?

2.8 A

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4.0 A

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5.6 A

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8.0 A

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Solution

The correct option is C $5.6 A$
We know Power $P_{d c} = I^{2} \times R$
Power desssipatied when current flowing is 2A
$P d_{c} = 4 \times R$
now $P A_{C} = I^{2} r m s \times R$
where $I_{r m s} =$ root square value of AC current.
Now according to question
$P_{a c} = 4 \times P_{d c} I^{2} r m s = 4 \times 4 I r m s = 4 A$
Now if the AC signal is sinusoidal,
$I_{P} = 1.414 \times 4 = 5.656 A$

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What is the approximate peak value of an alternating current producing four times the heat product per second by a steady current 2 A in a resistor ?

The correct option is C 5.6AWe know Power Pdc=I2×RPower desssipatied when current flowing is 2A Pdc=4×Rnow PAC=I2rms×Rwhere Irms=root square value of AC current.Now according to question Pac=4×PdcI2rms=4×4Irms=4ANow if the AC signal is sinusoidal,IP=1.414×4=5.656A

What is the approximate peak value of an alternating current producing four times the heat product per second by a steady current $2$ A in a resistor ?