What is the approximate percentage composition by mass of the element oxygen in the compound $H C l O_{4}$ ?

16

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35

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50

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64

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75

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Solution

The correct option is E $64$ %
$M o l e c u l a r w e i g h t o f : H = 1, C l = 35.43, O = 16 M o l e c u l a r w e i g h t o f c o m p o u n d = 1 + 35.43 + 4 * 16 = 100.43 P e r c e n t a g e c o m p o s i t i o n o f O = (64 / 100.43) * 100 = 64$

Suggest Corrections

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H C I O_{4}

(H = 1, N = 14, O_{s} = 16)

(K C C O_{3})

K = 39, C l = 35.5

O = 16

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M g_{2} P_{2} O_{7}

M g_{2} P_{2} O_{7}

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