Question

What is the approximate slope of a line perpendicular to the line $\sqrt{11}x+\sqrt{5}y=2$?

• A. $0.67$
• B. $0.93$
• C. $1.07$
• D. $1.53$
• E. $1.82$

Answer 1

The correct option is A $0.67$

Slope of the line $m_1=-\frac{\sqrt{11}}{\sqrt{5}}$

Let slope of the line perpendicular to this line is $m_2$

then $m_1{m}_2=-1$

$-\frac{\sqrt{11}}{\sqrt{5}}\times m_2=-1$

$m_2=\sqrt{\frac{5}{11}}$

$m_2=0.67$.