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Ways of Representing the Concentration of a Solution

What is the a...

Question

What is the aq.ammonia conentration of a solution prepared by dissolving $0.15$ mole of $N H_{4}^{+} C H_{3} C O O^{-}$ in $1$ L $H_{2} O . [K_{a (C H_{3} C O O H)} = 1.8 \times 10^{- 5}; K_{b (N H_{4} O H)} = 1.8 \times 10^{- 5}]$

8.3 \times 10^{- 4}

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0.15

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6.4 \times 10^{- 4}

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3.8 \times 10^{- 4}

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Solution

The correct option is A $8.3 \times 10^{- 4}$

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Similar questions

C H_{3} C O O H

0.01

C H_{3} C O O^{-} N H_{4}^{+}

1 L

H_{2} O

[K_{a (C H_{3} C O O H)} = 1.8 \times 10^{- 5}; K_{b (N H_{4} O H)} = 1.8 \times 10^{- 5}]

0.01 M C H_{3} C O O H

1.8 \times 10^{- 5}

C H_{3} C O O^{-}

H C l

C H_{3} C O O N H_{4}

K_{a} (C H_{3} C O O H) = K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}

0.15 m o l e

{N H}_{4} O H

0.25 m o l e

{N H}_{4} C l

K_{b}

{N H}_{4} O H

1.8 \times 10^{- 5}

100 mL

0.4 M C H_{3} C O O H

100 mL

0.2 M N a O H

[H_{3} O^{+}]

[K_{a} (C H_{3} C O O H) = 1.8 \times 10^{- 5}]

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