Question

What is the area bounded by the parabola $y=x^2$ and the lines $x=-2$ and $x=1$ ?

Answer 1

$Area={\int }_{-2}^0{x}^{2}dx+{\int }_0^1{x}^{2}dx=\frac{x^3}{3}{\int }_{-2}^1=\frac{1}{3}-(-\frac{8}{3})=\frac{9}{3}$

$Area=3$ $sqr$ $unit$.