Question

What is the area(in ${cm}^2$) of this triangle?
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Answer 1

$\text{(Area of triangle)}$ $=\frac{1}{2}\times \text{base}\times \text{height}$

The three sides are $\text{(10cm, 6cm and 8cm)}$.

${10}^2=6^2+8^2$

The sides satisfy Pythagoras theorem. Hence, this is a right-angled triangle, with the sides $\text{6cm}$ and $\text{8cm}$ being the base and the height, respectively.

Hence, $Area=\frac{1}{2}\times 6\times 8$ ${cm}^2$
$=24c{m}^2$