What is the area of a rectangle (in square units) having length $5 x y$ and breadth $8 x y^{2}$ ?

40x²y³

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40x²y²

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40xy³

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40xy

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Solution

The correct options are
A
40x²y³

C
40xy³

Area of any rectangle is the product of its length and breadth.
If 'l' is the length and 'b' is the breadth,
$A r e a = l \times b$
Here,
$= l \times b = 5 x y \times 8 x y^{2} = 40 x^{2} y^{3} s q u a r e u n i t s$

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