What is the area of a rectangle with length x -2 cm and breadth x -6 cm -A- x 3-8 x -12 cm 2B- x2-8 x-6 cm 2C- x 2-6 x -12 cm 2D- x2-8 x-12 cm 2

The correct option is D (x^2+8x+12)cm^2Given: l= nbsp; nbsp;(x+2) cm b = (x+6) cm Area of a rectangle = length × breadth Area = (x+2)(x+6) =x(x+6)+2(x+6) ...

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Standard VII

Mathematics

(x + a)(x +b)= x^2 + x(a+ b) + ab

What is the a...

Question

What is the area of a rectangle with length $(x + 2) c m$ and breadth $(x + 6) c m$ ?

(x^{3} + 8 x + 12) c m^{2}

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(x^{2} + 8 x + 6) c m^{2}

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(x^{2} + 6 x + 12) c m^{2}

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(x^{2} + 8 x + 12) c m^{2}

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Solution

The correct option is D $(x^{2} + 8 x + 12) c m^{2}$
Given: $l = (x + 2) c m b = (x + 6) c m$
Area of a rectangle = length × breadth
$A r e a = (x + 2) (x + 6) = x (x + 6) + 2 (x + 6) = x^{2} + 6 x + 2 x + 2 \times 6 = (x^{2} + 8 x + 12) c m^{2}$

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What is the area of a rectangle with length (x+2)cm and breadth (x+6)cm?

The correct option is D (x2+8x+12)cm2Given: l=(x+2)cmb=(x+6)cm Area of a rectangle = length × breadth Area=(x+2)(x+6)=x(x+6)+2(x+6)=x2+6x+2x+2×6=(x2+8x+12)cm2

What is the area of a rectangle with length $(x + 2) c m$ and breadth $(x + 6) c m$ ?

The correct option is D $(x^{2} + 8 x + 12) c m^{2}$
Given: $l = (x + 2) c m b = (x + 6) c m$
Area of a rectangle = length × breadth
$A r e a = (x + 2) (x + 6) = x (x + 6) + 2 (x + 6) = x^{2} + 6 x + 2 x + 2 \times 6 = (x^{2} + 8 x + 12) c m^{2}$