Question

What is the area of a trapezium whose parallel sides are 57 cm and 39 cm and the distance between them is 28 cm?

• A. $1344c{m}^2$
• B. $1244c{m}^2$
• C. $1144c{m}^2$
• D. $1044c{m}^2$

Answer 1

The correct option is A $1344c{m}^2$

Area of trapezium = $\frac{1}{2}\times \text{(sum of parallel sides)}\times \text{height}$​

Sum of parallel sides = 57 + 39 = 96 cm​

Height = 28 cm​

Therefore, Area of trapezium​

= $\frac{1}{2}\times \left(96\right)\times 28$

= $1344c{m}^2$

​
Answer: (A) $1344c{m}^2$