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Question

What is the area of a triangle whose three sides are a = 3 cm, b = 4 cm, c = 5 cm


A

12 sq.unit

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B

6 sq.unit

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C

12 sq.unit

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D

18 sq.unit

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Solution

The correct option is B

6 sq.unit


Area of triangle having sided a, b, and c is 2s(sa)(sb)(sc), here s = a+b+c2

Substituting the value of s = 3+4+52 = 6, we get

Area = 26(63)(64)(65) = 26(3)(2)(1) = 6 sq.unit


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