What is the area of a triangle whose three sides are a = 3 cm, b = 4 cm, c = 5 cm
6 sq.unit
Area of triangle having sided a, b, and c is 2√s(s−a)(s−b)(s−c), here s = a+b+c2
Substituting the value of s = 3+4+52 = 6, we get
Area = 2√6(6−3)(6−4)(6−5) = 2√6(3)(2)(1) = 6 sq.unit