What is the area of a triangle whose three sides are a -3 cm - b -4 cm - c -5 cmA- 12 sq-unitB- 6 sq-unitC- 12 sq-unitD- 18 sq-unit

The correct option is B 6 sq.unit Area of triangle having sided a, b, and c is √(s(s a)(s b)(s c)), here s = a+b+c/2 Substituting the value of s = 3+4+5/2 = 6 ...

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Standard IX

Mathematics

Area of Triangle of an Isosceles Triangle

What is the a...

Question

What is the area of a triangle whose three sides are a = 3 cm, b = 4 cm, c = 5 cm

12 sq.unit

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6 sq.unit

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12 sq.unit

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18 sq.unit

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Solution

The correct option is B
6 sq.unit

Area of triangle having sided a, b, and c is $\sqrt[2]{s (s - a) (s - b) (s - c)}$ , here s = $\frac{a + b + c}{2}$

Substituting the value of s = $\frac{3 + 4 + 5}{2}$ = 6, we get

Area = $\sqrt[2]{6 (6 - 3) (6 - 4) (6 - 5)}$ = $\sqrt[2]{6 (3) (2) (1)}$ = 6 sq.unit

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What is the area of a triangle whose three sides are a = 3 cm, b = 4 cm, c = 5 cm

The correct option is B 6 sq.unit Area of triangle having sided a, b, and c is 2√s(s−a)(s−b)(s−c), here s = a+b+c2 Substituting the value of s = 3+4+52 = 6, we get Area = 2√6(6−3)(6−4)(6−5) = 2√6(3)(2)(1) = 6 sq.unit