Distance between Two Points on the Same Coordinate Axes
What is the a...
Question
What is the area of a triangle whose vertices are (a, b + c), (a, b - c) and (-a, c)?
A
|2ab|
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B
|4ac|
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C
|2ac|
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D
Triangle can't be formed
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Solution
The correct option is C
|2ac|
Area of the triangle = 12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)] 12[a(b−c−c]+a(c−b−c)−a(b+c−b+c)] 12[a(b−2c)+a(−b)−a(2c)]=−2ac The area of a triangle can never be a negative quantity, so we always take the modulus of the value So, the area is |-2ac| =|2ac|