Question

What is the area of an equilateral triangle whose side is $\text{8 cm}$?

• A. $16\sqrt{3}{cm}^2$
• B. $16{cm}^2$
• C. $6\sqrt{3}{cm}^2$
• D. $16\sqrt{5}{cm}^2$

Answer 1

The correct option is A

$16\sqrt{3}{cm}^2$

Area of an equilateral triangle whose side is $\text{8 cm}$ $=\frac{\left(\sqrt{3}\right)}{4}{a}^2$ ${cm}^2$, where a $=\text{8 cm}$
$=\frac{\left(\sqrt{3}\right)}{4}$ $\times$ $8^2$ ${cm}^2$
$=\frac{\left(\sqrt{3}\right)}{4}$ $\times 64$ ${cm}^2$
$=16\sqrt{3}{cm}^2$