Question

What is the area of an isosceles right angled triangle of equal sides 16 cm each?

• A. 128 $c{m}^2$
• B. 164 $c{m}^2$
• C. 172 $c{m}^2$
• D. 184 $c{m}^2$

Answer 1

The correct option is A 128 $c{m}^2$

An isosceles right triangle has two congruent sides which are its two perpendicular legs (the two shorter sides) that form the right angle of the triangle. The given triangle can be shown as below:

For a right angled triangle,
Area = $\frac{1}{2}\times base\times height$

Given,
Base of the triangle = 16 cm and height of the triangle = 16 cm
So, area of the triangle
= $\frac{1}{2}$ x base x height
= $\frac{1}{2}$ x 16 x 16
= 128 $c{m}^2$