Question

What is the area of the given figure?

• A. 2296 $m^2$
• B. 3064 $m^2$
• C. 3196 $m^2$
• D. 3296 $m^2$

Answer 1

The correct option is B 3064 $m^2$

The given figure can be thought of as a combination of 3 figures, 2 semi-circles of diameter 28m on the sides and 1 rectangle in the middle with length 60m and breadth 28m.


Area of the given figure = area of two semi-circles + area of rectangle

The area of the two semi-circles can be found out as 2 x area of 1 semi circle.
Area of a semi circle is given by $\frac{1}{2}\times \pi \times r^2$ .
Given, diameter of semi-circle = 28 m
So, radius of semi-circle
$=\frac{1}{2}\left(Diameter\right)=\frac{1}{2}\times 28m=14m$

Therefore, area of the two semi-circles
$=2\times \frac{1}{2}\times \frac{22}{7}\times (14{)}^2=\frac{22}{7}\times 14\times 14=22\times 2\times 14=616m^2$

And area of the rectangle
= length x breadth
= 60 x 28
= 1680 $m^2$

So, total area of the figure = Area of two semi-circles + area of the rectangle = 616 + 1680 = 2296 $m^2$