2
Question
What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realisefrom your answer why ordinary capacitors are in the range of μF orless. However, electrolytic capacitors do have a much largercapacitance (0.1 F) because of very minute separation between theconductors.]
Open in App
Solution
Given: The capacitance of the parallel capacitor is 2 F and the separation between the plates is 0.5 cm .
The capacitance of a parallel plate capacitor is given as,
C = ε 0 A d
Where, the permittivity of free space is ε 0 , the separation between the plates is d and the area of the plates is A .
By substituting the given values in the above formula, we get
2 = 8.85 × 10 − 12 × A 0.5 × 10 − 2 A = 1130 km 2
Thus, the area of plates is very large so the capacitance should be taken in the range of μF to avoid this situation.
Given: The capacitance of the parallel capacitor is
The capacitance of a parallel plate capacitor is given as,
Where, the permittivity of free space is
By substituting the given values in the above formula, we get
Thus, the area of plates is very large so the capacitance should be taken in the range of
Suggest Corrections
1
Similar questions