What is the area of the rectangle having a length of 2 a-b cm and breadth of b cm -A- 2 a b-b cm 2B- 2 ab 2- b cm 2C- 2 a 2 b - b cm 2D- 2 a b-b2 cm 2

The correct option is D (2ab +b^2) cm^2 nbsp; nbsp;Given, nbsp; Length of the rectangle =2a +b cm Breadth of the rectangle = b cm Area of the rectangle ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of a Binomial by a Monomial

What is the a...

Question

What is the area of the rectangle having a length of (2a + b) cm and breadth of b cm?

(2 a b + b) c m^{2}

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(2 a b^{2} + b) c m^{2}

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(2 a^{2} b + b) c m^{2}

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(2 a b + b^{2}) c m^{2}

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Solution

The correct option is D $(2 a b + b^{2}) c m^{2}$
Given,
Length of the rectangle $= 2 a + b$ cm
Breadth of the rectangle $= b$ cm

Area of the rectangle
$= l e n g t h \times b r e a d t h$
$= (2 a + b) \times b$
$= (2 a b + b^{2}) c m^{2}$

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What is the area of the rectangle having a length of (2a + b) cm and breadth of b cm?

The correct option is D (2ab+b2) cm2 Given, Length of the rectangle =2a+b cm Breadth of the rectangle =b cm Area of the rectangle =length×breadth =(2a+b)×b =(2ab+b2) cm2

The correct option is D $(2 a b + b^{2}) c m^{2}$
Given,
Length of the rectangle $= 2 a + b$ cm
Breadth of the rectangle $= b$ cm

Area of the rectangle
$= l e n g t h \times b r e a d t h$
$= (2 a + b) \times b$
$= (2 a b + b^{2}) c m^{2}$