What is the area of the rhombus ABCD below if AC=12 cm and BE= 8 cm?
96 cm2
The diagonals of a rhombus bisect each other. Therefore, in the given figure:
⇒BE=DE
⇒BD=2×BE
⇒BD=2×8=16 cm
Area of a rhombus equals half the product of length of the two diagonals.
⇒Area of ABCD = 12×AC×BD
⟹Area of ABCD= 12×12×16=96 cm2.