What is the area of the rhombus ABCD below, if AC=12cm and BE= 16cm.
192 cm2
The diagonals of a rhombus bisect each other. Therefore in the above figure:
⇒BE=DE
⇒BD=2×BE
⇒BD=2×16=32cm
Area of a rhombus = half of the product of length of the two diagonals.
⇒Area=12×AC×BD
⇒Area=12×12×32=192cm2.