What is the area of the rhombus ABCD below if AC = 6 cm and BE = 4 cm?
24 cm2
The diagonal AC of the rhombus ABCD divides it into two triangles of equal areas.
Now, area of ΔABC=12×Base×Height=12×4×6=12 cm2
∴ Area of the rhombus ABCD=2×Area of ΔABC
=2×12=24cm2