What is the area of the semicircle if its circumference is $12.5 c m$ ?

6.28

c m^{2}

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4.28

c m^{2}

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2.28

c m^{2}

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1.28

c m^{2}

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Solution

The correct option is B $6.28$ $c m^{2}$
Circumference of a semicircle $= π r$
$12.5 = π r$
$r = 3.98 \approx 4$
Area of the semicircle $= \frac{1}{2} π r$
$= \frac{1}{2} π (4)$
$= 6.28$ $c m^{2}$

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