What is the area of the table whose sides measure 1m 20 cm in length and 2m 50 cm in breadth? [2 MARKS]

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Solution

Steps: 1 Mark
Answer: 1 Mark

$\Rightarrow$ Length (l) = 1m 20cm

1 m= 100 cm

= $(1 + \frac{20}{100}) m = 1.2 m$

$\Rightarrow$ Breadth (b) = 2m 50cm

= $(2 + \frac{50}{100}) m = 2.5 m$

$\Rightarrow$ Area = $l \times b = 1.2 m \times 2.5 m = 3 m^{2}$

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What is the area of the table whose sides measure 1m 20 cm in length and 2m 50 cm in breadth? [2 MARKS]

Steps: 1 Mark Answer: 1 Mark ⇒ Length (l) = 1m 20cm 1 m= 100 cm = (1+20100)m=1.2m ⇒ Breadth (b) = 2m 50cm = (2+50100)m=2.5m ⇒ Area = l×b=1.2 m×2.5 m=3 m2

Steps: 1 Mark
Answer: 1 Mark

$\Rightarrow$ Length (l) = 1m 20cm

1 m= 100 cm

= $(1 + \frac{20}{100}) m = 1.2 m$

$\Rightarrow$ Breadth (b) = 2m 50cm

= $(2 + \frac{50}{100}) m = 2.5 m$

$\Rightarrow$ Area = $l \times b = 1.2 m \times 2.5 m = 3 m^{2}$