What is the area of the triangle having sides of length $7 c m, 8 c m$ and $9 c m$ ?

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Solution

Length of sides are 7 cm, 8 cm and 9 cm
semi-perimeter $= \frac{(7 + 8 + 9)}{2} c m$
$S = 12 c m$
using Heuron's formula, Area of triangle
$= \sqrt{S (S - a) (S - b) (S - c)}$ ,where a,b,c, are sides of triangle
$= \sqrt{12 \times 5 \times 4 \times 3} = \sqrt{4 \times 4 \times 3 \times 3 \times 5}$
$= 12 \sqrt{5} c m^{2}$

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II.Two obtuse angles.

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Question 1 (a)

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