What is the area of this trapezium?

ED and BC are perpendicular to DC. ED = a, BC = b, DC = c

$\frac{1}{2}$ (c+b)(b+a)

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$\frac{1}{2}$ c(a+b)

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$\frac{1}{2}$ a(c+b)

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$\frac{1}{2}$ b(c+a)

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Solution

The correct option is B
$\frac{1}{2}$ c(a+b)

area of a trapezium FEDB = $\frac{1}{2}$ [(distance between parallel sides)(sum of the parallel sides)] = $\frac{1}{2}$ c(a + b)

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What is the area of this trapezium? ED and BC are perpendicular to DC. ED = a, BC = b, DC = c

The correct option is B 12c(a+b) area of a trapezium FEDB = 12[(distance between parallel sides)(sum of the parallel sides)] = 12c(a + b)

What is the area of this trapezium?

ED and BC are perpendicular to DC. ED = a, BC = b, DC = c

The correct option is B
$\frac{1}{2}$ c(a+b)

area of a trapezium FEDB = $\frac{1}{2}$ [(distance between parallel sides)(sum of the parallel sides)] = $\frac{1}{2}$ c(a + b)