What is the area of this trapezium?

ED and BC are perpendicular to DC. ED = a, BC = b, DC = c

(1/2)(c+b)(b+a)

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(1/2)c(a+b)

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(1/2)a(c+b)

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(1/2)b(c+a)

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Solution

The correct option is B
(1/2)c(a+b)

area of a trapezium FEDB = $\frac{1}{2}$ [(distance between parallel sides)(sum of the parallel sides)] = $\frac{1}{2}$ c(a + b)

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$1 - 2 a b - (a^{2} + b^{2}) = ? (a) (1 + a - b) (1 + a + b) (b) (1 + a + b) (1 - a + b) (c) (1 + a + b) (1 - a - b) (d) (1 + a - b) (1 - a + b)$

\vec{A B} + \vec{A E} + \vec{B C} + \vec{D C} + \vec{E D} = k \vec{A C},

\vec{A B} + \vec{B C} + \vec{C D} + \vec{D E} + \vec{E A} = \vec{0}

\vec{A B} + \vec{A E} + \vec{B C} + \vec{D C} + \vec{E D} + \vec{A C} = 3 \vec{A C}

What is the area of this trapezium?

ED and BC are perpendicular to DC. ED = a, BC = b, DC = c

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