What is the area of triangle XYZ, where coordinates of points X, Y and Z are (4, 5), (-1, -6) and (-4, -5) respectively?
A
19 Square units
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B
29 Square units
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C
38 Square units
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D
58 Square units
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Solution
The correct option is A
19 Square units Area of ΔXYZ =12∣∣
∣
∣∣4(−6)−(−5)+(−1)((−5)−5)+(−4)(5−(−6))∣∣
∣
∣∣=12|4(−1)+(−1)(−10)+(−4)(11)|=12|−4+10−44|=12|−38|=382=19sq.units