What is the arithmetic mean of first 20 terms of an AP whose first term is 5 and 4th term is 20?
A
50
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B
52.5
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C
55
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D
57.5
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Solution
The correct option is B 52.5 a=5,t4=a+3d=20⇒d=5 A.M is the middle number =average of 10th & 11th number =50+552=52.5 (or) A.M=Snn=12[2a+(n−1)d] where a=5, n =20, d=5 ⇒ A.M =52.5