CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the average of all five digit numbers that can be formed using all the digits 1, 2, 3, 4, 5 exactly once?

A
33322
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
33333
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
32235
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
33225
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 33333

Option(b)

To find the average of all numbers, we need to find the sum of all the possible numbers and divide it by the total such numbers possible.The sum of all possible numbers can be found using the formula

(n-1)!(sum of digits)(1111…n times)

here n=5

(5-1)!(15)(11111)= 4!(15)(11111)

Total number of such possible cases= 5!

Average= 3999960/5! = 33333

Short cut: - If we arrange given numbers, These numbers will be in A.P.

Ao, A.M. of these numbers = (First term + last term)/2

(12345+54321 )/2 = 33333


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Averages
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon