What is the average of squares of consecutive odd numbers between $1$ and $13$ ?

49

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51

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53

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57

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Solution

The correct option is D $57$
The consecutive odd numbers from $1$ to $13 = 3, 5, 7, 9, 11$
Thus required average = $\frac{3^{2} + 5^{2} + 7^{2} + 9^{2} + 11^{2}}{5} = \frac{9 + 25 + 49 + 81 + 121}{5} = \frac{285}{5} = 57$

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-13 +(-69)+57-(-89)-(53+(-49) ?

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