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Alternating Current Applied to an Inductor

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Question

What is the average power (in W) delivered by the source?

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Solution

$P = \frac{V_{r m s}^{2}}{R} = \frac{(150 / \sqrt{2})^{2}}{150} = 75 W$

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Q. Assertion :An inductor, a capacitor and a resistor are connected in series.
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