What is the average translational kinetic energy of a molecule of an ideal gas at temperature of $27^{\circ} C$

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Solution

Translational kinetic energy is given by the formula

$E_{T} = \frac{3}{2} k T$

$E_{T} = \frac{3}{2} (1.38 X 10^{- 23}) (300) = 6.21 X 10^{- 21} J$

Answer is $6.21 X 10^{- 21} J$

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