wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the average velocity during time interval t=2 s to t=5 s, in the following position time curve?

A
2 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.2 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.4 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 23 m/s
Average velocity can be calculated from a position-time graph as change in position divided by the corresponding change in time.
Average velocity for the time interval (t=2 s to t=5 s) is

=ΔxΔt=6452=23 m/s

flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon