Question

What is the average velocity for the trip? (in km/h)

• A. $98.5$
  
• B. $98$
  
• C. $96$
  
• D. $97$
  

Answer 1

The correct option is A $98.5$

The average velocity is ratio of net displacement to the total traveled time.

By cosine theorem, the net displacement is $OB=\sqrt{O{A}^2+A{B}^2-2.OA.ABcos(90+26)}=\sqrt{(89{)}^2+(141{)}^2-2\left(89\right)\left(141\right)cos116}=197km$

Total traveled time is $t=1hr+1hr=2hr$

So, average velocity is $v_{avg}=\frac{OB}{t}=\frac{197}{2}=98.5km/s$