Question

What is the bond order in ${{\mathrm{NO}}_2}^{+}$?

Answer 1

Bond Order:

• Bond order is defined as the ratio of the number of bonds on all possible sides to the total number of resonating structures.

The formula used for calculation of bond order:

• $\mathrm{Bond}\mathrm{order}=\frac{\mathrm{Number}\mathrm{of}\mathrm{bonds}\mathrm{in}\mathrm{all}\mathrm{possible}\mathrm{sides}}{\mathrm{Resonating}\mathrm{structrures}}$

Calculation for bond order of ${{\mathrm{NO}}_2}^{+}$:

• For calculating bond order of ${{\mathrm{NO}}_2}^{+}$, resonating structures are required:
• ${{\mathrm{NO}}_2}^{+}$has two resonating structures.
• The number of bond pairs in ${{\mathrm{NO}}_2}^{+}$are 4 while 0 zero lone pairs are present.
• The structure of ${{\mathrm{NO}}_2}^{+}$is as follows:

$$\begin{gathered} \mathrm{Bond}\mathrm{order}=\frac{\mathrm{Number}\mathrm{of}\mathrm{bonds}\mathrm{in}\mathrm{all}\mathrm{possible}\mathrm{sides}}{\mathrm{Resonating}\mathrm{structrures}} \\ \mathrm{Bond}\mathrm{order}=\frac{4}{2}=2 \end{gathered}$$

Thus, the bond order of ${{\mathrm{NO}}_2}^{+}$is $2$.