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Nitrogen

What is the b...

Question

What is the bond order of N-N bond in $N_{2} O$ ?

A

1

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B

1.5

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C

2

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D

2.5

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Solution

The correct option is D 2.5
Bond order will be $\frac{T o t a l n o . o f b o n d s}{T o t a l N o . o f c a n o n i c a l s t r u c t u r e s} = \frac{5}{2} = 2.5$
The third structure is not possible as nitrogen cannot have two negative charges so we will consider only two structures.
In 1st structure there are three bonds between both nitrogen and in second structure there are two bonds so total bonds is 5.

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Similar questions

Q. Calculate resonance energy of

N_{2} O

from the following data
Hence,

△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}

Assume structure

N^{Θ} = N^{⨁} = O

(N \equiv N) b o n d = 950 k J m o l^{- 1}

(N = N) b o n d = 420 k J

^{- 1}

O = O) b o n d = 500 k J m o l^{- 1}

(O = N) b o n d = 610 k J m o l^{- 1}

Q. Calculate resonance energy of

N_{2} O

from the following data
Hence,

△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}

Assume structure

N^{Θ} = N^{⨁} = O

(N \equiv N) b o n d = 950 k J m o l^{- 1}

(N = N) b o n d = 420 k J

^{- 1}

O = O) b o n d = 500 k J m o l^{- 1}

(O = N) b o n d = 610 k J m o l^{- 1}

Δ H_{f}^{o}

N_{2} O

82 k J / m o l

and bond energy for

N_{2}, N = N, O = O

N = O

946, 418, 498

607 k J / m o l

respectively. Resonance energy of

N_{2} O

Q. The nitrogen oxides that contain N – N bond(s) is:

Q. Calculate the resonance energy of

N_{2} O

from the following data:

△_{f} H^{\circ}

N_{2} O = 82 k J m o l^{- 1}

, standard bond enthalpies of

N = N, N = N, O = O

N = O

946, 418, 498

607 k J m o l^{- 1}

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