wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the buoyant force experienced by a cube of side 10 cm which is completely immersed in water?
(Take g=10 m s2 and density of water =1000 kg m3)

Open in App
Solution

Given,
Length of each side of the cube, l=10 cm=0.1 m
Density of water, ρ=1000 kg m3
Acceleration due to gravity, g=10 m s2
Volume of the cube, V=l3=(0.1)3=0.001 m3

Archimedes' principle states that the buoyant force acting on an object is equal to the weight of the fluid displaced by it.
In the given case, volume of cube is equal to the volume of water displaced.

Mass of water displaced (m) = Density of water × Volume of water displaced
m=1000 kg m3×0.001 m3
=1 kg

Weight of water displaced, W = mg
W=1×10 =10 N
Hence, the buoyant force is 10 N.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Buoyancy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon