What is the catalyst 'y' used in the water gas shift reaction?

Reaction 1: $C (r e d h o t c o k e) + H_{2} O (g) 1273 K ⟶ C O (g) + H_{2} (g)$

Reaction 2: $C O (g) + H_{2} (g) + H_{2} O (g) y (c a t a l y s t) ⟶ C O_{2} (g) + 2 H_{2} (g)$

$F e_{2} O_{3} / C r_{2} O_{3}$

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$V_{2} O_{5}$

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Ziegler Natta Catalyst

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Solution

The correct option is A
$F e_{2} O_{3} / C r_{2} O_{3}$

Industrially, the water-gas shift reaction is very crucial because it helps manufacture $H_{2}$ . Also, extraction of hydrogen from water gas makes the manufacture of $H_{2}$ much more feasible economically. Hydrogen is industrially very important as it plays a vital role in the manufacture of ammonia, methanol and many other useful hydrocarbons. Also hydrogen is very important in the petroleum and refinery industries. In modern industrial manufacturing processes, the second reaction:
$C O (g) + H_{2} (g) + H_{2} O (g) \to C O_{2} (g) + H_{2} (g)$ is carried out in several stages to optimize the yield of $H_{2}$ (g). For this many catalysts are utilized.

One of the most significant catalysts is
$F e_{2} O_{3} / C r_{2} O_{3}$ . None of the other three catalysts displayed here is used in this reaction.

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Similar questions

What is the catalyst 'y' used in the water gas shift reaction?

Reaction 1: $C (r e d h o t c o k e) + H_{2} O (g) 1273 K ⟶ C O (g) + H_{2} (g)$

Reaction 2: $C O (g) + H_{2} (g) + H_{2} O (g) y (c a t a l y s t) ⟶ C O_{2} (g) + 2 H_{2} (g)$

What is the catalyst 'y' used in the water gas shift reaction?

Reaction 1: $C (r e d h o t c o k e) + H_{2} O (g) 1273 K ⟶ C O (g) + H_{2} (g)$

Water gas

Reaction 2: $C O (g) + H_{2} (g) + H_{2} O (g) y (c a t a l y s t) ⟶ C O_{2} (g) + 2 H_{2} (g)$

Reaction 1:
$C (r e d h o t c o k e) + H_{2} O Water gas$ (g) $1273 K ⟶$ $C O (g) + H_{2} (g)$

Reaction 2: $C O (g) + H_{2} (g) + H_{2} O (g)$ $y (c a t a l y s t) ⟶ C O_{2} (g) + 2 H_{2} (g)$

What is the catalyst 'y' used in the water gas shift reaction?

Reaction 1: C(red hot coke) + $H_{2} O Water gas$ (g) $1273 K ⟶$ $C O (g) + H_{2} (g)$

Reaction 2: $C O (g) + H_{2} (g) + H_{2} O (g)$ $y (c a t a l y s t) ⟶ C O_{2} (g) + 2 H_{2} (g)$

C o (g) + H_{2} (g) [X] \to H C H O (g)

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