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Question

What is the cell potential (standard emf, Eo) for the reaction below ?
[Eo(Fe2+(aq)/Fe)=0.44V and
Eo(O2(g)/H2O/OH)=+0.4V]


2Fe(s)+O2(g)+2H2O(l)2Fe2+(aq)+4OH(aq)

A
Eo cell = - 0.48 V
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B
Eo cell = - 0.04 V
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C
Eo cell = + 0.84 V
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D
Eo cell = + 1.28 V
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Solution

The correct option is D Eo cell = + 0.84 V
Eo cell =Eo cathode Eo anode
=0.40(0.44)=0.84V

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