Question

What is the center of the ellipse?
$(x-1{)}^2$ +$\frac{y^2}{25}$ = $1$

• A. $(0$, $0)$
• B. $(1$, $5)$
• C. $(1$, $0)$
• D. $(0$, $1)$

Answer 1

Answer: (C)

$(1$, $0)$

$(x-1{)}^2+\frac{y^2}{25}=1$

$(x-1{)}^2+\frac{(y-0{)}^2}{25}=1---(i)$

Comparing it with standard ellipse $\frac{x^2}{A^2}+\frac{y^2}{B^2}=1$ with centre $(0,0)$.

In $\left(i\right)$ we can see origin is shifted to $(1,0)$.

So centre is $(1,0)$.