Question

What is the chance of throwing at least $7$ in a single cast with $2$ dice?

• A. $\frac{5}{12}$
• B. $\frac{7}{12}$
• C. $\frac{1}{4}$
• D. $\frac{17}{36}$

Answer 1

Answer: (B)

$\frac{7}{12}$

Given: $2$ dice thrown

To find: the chance of throwing at least $7$

Sol: According to the question, $n\left(S\right)=6\times 6=36$

Favorable outcomes for getting at least $7$ are $(1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2)$

$(6,3),(6,4),(6,5),(6,6)$

$n\left(E\right)=21$

Hence, the chance of throwing at least $7$ $=\frac{21}{36}=\frac{7}{12}$