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Question

# What is the chance that a leap year, selected at random will contain 53 Sundays?

A
17
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B
27
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C
37
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D
47
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Solution

## The correct option is B 27 We know that a leap year has 366 days and thus a leap year has 52 weeks and 2 days over. The two left over (successive days have the following likely cases: (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday ∴ Number of exhaustive cases 'n' = 7 Out of these, the favorable cases are (i) and (vii) ∴ Number of favorable cases 'm' = 2 ∴ Probability of having 53 Sundays=27

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