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Question

What is the chance that a leap year, selected at random will contain 53 Sundays?

A
17
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B
27
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C
37
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D
47
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Solution

The correct option is B 27
We know that a leap year has 366 days and thus a leap year has 52 weeks and 2 days over.

The two left over (successive days have the following likely cases:

(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday

Number of exhaustive cases 'n' = 7

Out of these, the favorable cases are (i) and (vii)

Number of favorable cases 'm' = 2

Probability of having 53 Sundays=27

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